20=1/2(-9.8)t^2

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Solution for 20=1/2(-9.8)t^2 equation: 



20=1/2(-9.8)t^2

We move all terms to the left:

20-(1/2(-9.8)t^2)=0



Domain of the equation: 2(-9.8)t^2)!=0

t∈R



We multiply all the terms by the denominator


-(1+20*2(-9.8)t^2)=0



We calculate terms in parentheses: -(1+20*2(-9.8)t^2), so:

1+20*2(-9.8)t^2

determiningTheFunctionDomain
20*2(-9.8)t^2+1

Wy multiply elements

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We use the square of the difference formula

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